(x^2-4x)^2+7(x^2-4x)=-12

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Solution for (x^2-4x)^2+7(x^2-4x)=-12 equation: 



(x^2-4x)^2+7(x^2-4x)=-12

We move all terms to the left:

(x^2-4x)^2+7(x^2-4x)-(-12)=0

We add all the numbers together, and all the variables

(x^2-4x)^2+7(x^2-4x)+12=0

We multiply parentheses

7x^2+(x^2-4x)^2-28x+12=0

We add all the numbers together, and all the variables

7x^2-28x+(x^2-4x)^2+12=0

We move all terms containing x to the left, all other terms to the right

7x^2-28x+(x^2-4x)^2=-12

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